数控技术c语言直线、圆弧插补程序【研究分析】

以下是直线差补c语言程序，后面还有圆弧差补，数控老师布置的作业，没办法，自己编的，运行时没问题，保证质量，#include #include main() int x, y,x2,y2,dx, dy, n, k, i, f,a; printf (请输入起始点：n);scanf(%d%d,&x,&y); printf(请输入终止点：n);scanf(%d%d,&x2,&y2); dx=abs(x2-x); dy=abs(y2-y); n=dx+dy;printf(步数n=%dn,n); if(x20) if(y20) k=1; else k=4; else if(y20) k=2; else k=3; printf(相限k=%dn,k); for (i=0,f=0;i= 0) switch (k) case 1:x+; printf(%d %dn,x ,y); f-=dy; continue; case 2:y+; printf(%d %dn,x,y); f-=dx; continue; case 3:x-; printf(%d %dn,x,y); f-=dy; continue; case 4:y-; printf(%d %dn,x,y); f-=dx; continue; else switch (k) case 1: y+; printf(%d %dn,x ,y); f+=dx; continue; case 2: x-; printf(%d %dn,x,y); f+=dy; continue; case 3:y-; printf(%d %dn,x,y); f+=dx; continue; case 4:x+; printf(%d %dn,x,y); f+=dy; continue; 下面为圆弧差补c语言程序#includestdio.h#includemath.h#includectype.hmain() int X0,Y0,Xe,Ye,a,I,J,Ie,Je,f; printf(请输入圆弧上的两个点：); scanf(%d %d %d %d,&X0,&Y0,&Xe,&Ye); printf(X0,Y0)=(%d,%d),(Xe,Ye)=(%d,%d),X0,Y0,Xe,Ye); printf(请选择圆弧加工方向，逆时针加工请输入1，顺时针加工请输入2n); scanf(%d,&a); I=X0,J=Y0,Ie=Xe,Je=Ye,f=0; switch(a) case 1: loop: while(Ie!=I)|(Je!=J) if(I=0&J0) if(f=0)f=f-2*I+1;I=I-1;printf(f=%dI=%dJ=%dn,f,I,J); elsef=f+2*J+1;J=J+1;printf(f=%dI=%dJ=%dn,f,I,J);goto loop; if(I=0) if(f=0)f=f-2*J+1;J=J-1;printf(f=%dI=%dJ=%dn,f,I,J); elsef=f-2*I+1;I=I-1;printf(f=%dI=%dJ=%dn,f,I,J);goto loop; if(I=0&J=0)f=f+2*I+1;I=I+1;printf(f=%dI=%dJ=%dn,f,I,J); elsef=f-2*J+1;J=J-1;printf(f=%dI=%dJ=%dn,f,I,J);goto loop; if(I0&J=0)f=f+2*J+1;J=J+1;printf(f=%dI=%dJ=%dn,f,I,J); elsef=f+2*I+1;I=I+1;printf(f=%dI=%dJ=%dn,f,I,J);goto loop; case 2: loop1: while(Ie!=I)|(Je!=J) if(I=0&J0) if(f=0)f=f-2*J+1;J=J-1;printf(f=%dI=%dJ=%dn,f,I,J); elsef=f+2*I+1;I=I+1;printf(f=%dI=%dJ=%dn,f,I,J);goto loop1; if(I=0) if(f=0)f=f+2*I+1;I=I+1;printf(f=%dI=%dJ=%dn,f,I,J); elsef=f+2*J+1;J=J+1;printf(f=%dI=%dJ=%dn,f,I,J);goto loop1; if(I=0&J=0)f=f+2*J+1;J=J+1;printf(f=%dI=%dJ=%dn,f,I,J); elsef=f-2*I+1;I=I-1;printf(f=%dI=%dJ=%dn,f,I,J);goto loop1; if(I0&J=0)f=f-2*I+1;I=I-1;printf(f=%dI=%dJ=%dn,f,I,J); elsef=f-2*J+1;J=J-1;printf(f=%dI=%dJ=%dn,f,I,J);goto loop1; system(pause); 3技术l类别