五四制鲁教版六年级数学下册-第六章--整式的乘除---同底数幂的除法课件

,单击此处编辑母版标题样式,单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,*,*,同底数幂的除法,鲁教版五四六年级下,第,6,章整式的乘除,6.3,B,D,1,2,3,4,5,D,B,6,7,8,B,答案呈现,温馨提示,：,点击 进入讲评,习题链接,9,B,10,D,A,11,12,D,D,A,3,13,14,15,16,17,18,答案呈现,温馨提示,：,点击 进入讲评,习题链接,19,20,6,计算,x4x,结果正确的是,(,),A,x4,B,x3,C,x2,D,x,B,1,下列计算正确的是,(,),A,a2a3,a6,B,a2,a3,a5,C,(a2)3,a8,D,a3a2,a,2,D,3,D,下列运算：,a2a3,a6,；,(a3)2,a6,；,a5a5,a,；,(ab)3,a3b3.,其中结果正确的个数为,(,),A,1B,2,C,3D,4,B,4,某工厂生产,A,，,B,两种型号的螺丝，在,2020,年,12,月底时，该工厂统计了,2020,年下半年生产的两种型号螺丝的总量，据统计,2020,年下半年生产的,A,型号螺丝的总量为,a12,个，,A,型号螺丝的总量是,B,型号的,a4,倍，则,2020,年下半年该工厂生产的,B,型号螺丝的总量为,(,),A,a4,个,B,a8,个,C,a3,个,D,a48,个,B,5,【,点拨,】,由题可得，,2020,年下半年该工厂生产的,B,型号螺丝的总量为,a,12,a,4,a,8,(,个,),计算,x5m,3n,1(xn)2(,xm)2,的结果是,(,),A,x7m,n,1,B,x7m,n,1,C,x7m,n,1,D,x3m,n,1,6,B,【,点拨,】,x5m,3n,1,(xn)2,(,xm)2,x5m,3n,1,x2n,x2m,x5m,3n,1,2n,2m,x7m,n,1.,墨迹,覆盖了等式“,x3x,x2(x0)”,中的运算符号，则覆盖的是,(,),A,B,C,D,7,D,8,A,【,点拨,】,因为,a,4,b,2,0,，,所以,a,4,b,2.,所以,3,a,81,b,3,a,3,4,b,3,a,4,b,3,2,9.,若,m23,26,，则,m,等于,(,),A,2,B,4,C,6,D,8,9,D,10,D,11,A,12,如果,(,x,1),7,(1,x,),6,3,x,5(,x,1),，那么,x,的值为,_,3,【,点拨,】,因为,(,x,1),7,(1,x,),6,(,x,1),7,(,x,1),6,x,1(x1),，,所以,x,1,3,x,5,，,解得,x,3.,13,若,x,a,4,，,x,b,3,，,x,c,8,，则,x,2,a,b,c,的值为,_,6,【,点拨,】,因为,x,a,4,，,x,b,3,，,x,c,8,，,所以,x,2,a,b,c,(,x,a,),2,x,b,x,c,4,2,38,6.,14,若,2,x,a,，,4,y,b,，求,2,x,2,y,的值,(,用含,a,，,b,的式子表示,),15,化简：,(,x,y,),12,(,y,x,),2,(,y,x,),3,.,解：原式,(,x,y,),12,(,x,y,),2,(,x,y,),3,(,x,y,),11,或原式,(,y,x,),12,(,y,x,),2,(,y,x,),3,(,y,x,),11,.,【,点拨,】,本题应先将底数互为相反数的幂化为同底数幂再进行计算此题的易错之处是弄错符号,16,计算：,(1)(xn,1)4x2(xn,2)3(x2)n,；,解：原式,x4n,4,2(x3n,6x2n),x4n,6xn,6,x3n,；,(2)(aam,1)2,(a2)m,3a2,；,解：原式,a2m,4,a2m,6a2,a2m,4,a2m,4,0,；,(3)(3,a,2,),2,a,2,2,a,2,(,2,a,3,),2,a,2,.,解：,原式,9,a,4,2,a,4,4,a,6,a,2,9,a,4,2,a,4,4,a,4,11,a,4,.,17,(1),先化简，再求值：,(2,x,y,),13,(2,x,y,),3,2,(,y,2,x,),2,3,，,其中,x,2,，,y,1.,解：,原式,(2,x,y,),13,(2,x,y,),6,(2,x,y,),6,(2,x,y,),13,6,6,2,x,y,.,当,x,2,，,y,1,时，,原式,2,x,y,22,(,1),5.,(2),已知,x,a,3,，,x,b,6,，,x,c,12,，,求,x,2,a,b,c,的值,解：,因为,x,a,3,，,所以,x,2,a,(,x,a,),2,3,2,9.,所以,x,2,a,b,c,x,2,a,x,b,x,c,9612,18.,(3),已知,3,x,2,y,3,0,，求,10,3,x,10,2,y,.,解：因为,3x,2y,3,0,，,所以,3x,2y,3.,所以,103x102y,103x,2y,103,1000.,18,已知,2,a,4,，,2,b,6,，,2,c,12,(1),试说明：,a,b,c,1,；,解：,因为,2,a,4,，,2,b,6,，,2,c,12,，,所以,2,a,2,b,2,462,12,2,c,.,所以,a,b,1,c,，,即,a,b,c,1,；,(2),求,2,2,a,b,c,的值,解：,因为,2,a,4,，,2,b,6,，,2,c,12,，,所以,2,2,a,b,c,(2,a,),2,2,b,2,c,16612,8.,19,已知,3292x,127x,1,81,，求出式中的,x.,解：因为,3292x,127x,1,3234x,233x,3,32,4x,2,(3x,3),3x,1,81,34,，,所以,x,1,4,，,所以,x,3.,20,(2),已知,2,a,3,b,4,c,5,，求,4,a,8,b,16,c,的值,解：,因为,2,a,3,b,4,c,5,，,所以,4,a,8,b,16,c,2,2,a,2,3,b,2,4,c,2,2,a,3,b,4,c,2,5,32.,