复合轮系传动比计算

单击此处编辑母版标题样式,单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,*,复合轮系传动比,(Transmission ratio of compounding gear train),1,2,2,3,4,5,6,H,步骤:,1.区分轮系:,2.列相应轮系传,动比公式；,3.找相关条件；,4.联立求解未知,量。,如图示轮系:,定轴轮系:,基本周转轮系:,相关条件:,将(1),(2),(3)式联立,求解。,例一、区分轮系练习,1.,1,2,3,2,4,3,H,4,5,定 轴 轮 系：,基本周转轮系:,1,2,3,2,4,3,H,4,5,2.,2,2,1,3,4,H,周转轮系:,2,2,1,4,H,2,2,3,4,H,2,1,3,H,3.,1,2,3,4,5,H,6,7,1,2,6,7,周转轮系：,3,4,5,H,定轴轮系：,1,2,2,3,3,4,5,解：,1.区分轮系：,3,4,5,周转轮系：,1,2,2,3,5,定轴轮系：,2.分别列传动比公式：,(1),(2),3.相关条件：,4.联立求解：,由(1)式：,代入(2)式得：,1,2,2,3,3,4,5,1,2,2,3,3,5,4,解：,定轴轮系：,1,2,5,周转轮系：,2,3,3,5,4,例三、已知：图示轮系中,方向如图所示。求：,1,2,2,3,3,5,4,解：,1,2,5,2,3,3,5,4,(1),(2),(3),(3),由(1)式得：,由(2)式得：,1,2,2,3,3,5,4,1,1,2,3,4,5,6,7,H,A,H,1,1,2,3,4,5,6,7,H,A,H,解：,1)由同心条件,2),定轴轮系：,1,A,周转轮系:,1,2,3,4,H,5,6,7,H,由(2)得：,1,1,2,3,4,5,6,7,H,A,H,