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单击此处编辑母版标题样式,单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,*,*,【,题,1.4】,变量,A,、,B,、,C,为哪种取值时,函数值为,1,?,(,1,),分析:与或表达式中,任意一个与项值为,1,,则函数值为,1.,令与项,AB,值为,1,,则变量,A,、,B,、,C,的取值为,11x,,即,C,取,0,或,1,均可。,令与项,BC,值为,1,,则变量,A,、,B,、,C,的取值为,x11,,即,A,取,0,或,1,均可。,令与项,C,值为,1,,则变量,A,、,B,、,C,的取值为,0 x1,,即,B,取,0,或,1,均可。,解:,A,、,B,、,C,取值为,001,、,011,、,110,、,111,时,,Y,1,=1,;,(,4,)非与或表达式,通过变换转换为与或表达式。,【,题,1.6】,列出下列各函数的真值表,说明,Y,1,和,Y,2,有何关系。,(,2,),(3),A,B,C,Y,1,Y,2,Y,3,Y,4,0,0,0,0,0,1,0,1,0,0,1,1,1,0,0,1,0,1,1,1,0,1,1,1,1,1,0,0,0,0,0,0,0,0,0,0,1,1,1,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,0,Y,1,=Y,2,【,题,1.7】,逻辑函数,Y,1,Y,5,的真值表如表所示,试分别写出它们各自的标准与或表达式。,A,B,C,Y,1,Y,2,Y,3,Y,4,Y,5,0,0,0,0,0,0,0,1,0,0,1,1,0,1,1,0,0,1,0,1,0,1,1,0,0,1,1,0,1,0,1,1,1,0,0,1,0,1,0,0,1,0,1,0,1,0,0,0,1,1,0,0,1,0,0,1,1,1,1,1,1,0,1,0,【,题,1.8】,将下列函数展开成最小项表达式:,(,4,),解:,【,题,1.9】,用公式法将下列函数化简成为最简与或式:,(,7,),解:,单独化简有三种情况:(,A+D),、,(A+B),、,(B+D),与前一项结合,选择(,A+B,),【,题,1.10】,求下列函数的反函数(德,摩根定理),并将求出的反函数化简成为最简与或式,:,(3),解:,【,题,1.11】,写出图,P1.11,(,a,),(,f,)所示各函数的最简与或表达式:,(d),00,01,11,10,00,01,11,10,1,1,1,1,1,1,1,1,1,0,0,0,0,0,0,0,【,题,1.16】,写出图,P1.16,所示逻辑图的输出函数表达式,列出它们的真值表:,1,&,&,&,&,&,1,1,&,1,1,S,i,C,i,A,i,B,i,C,i-1,1,&,(a),补充习题:,判断图中各卡诺图的圈法是否正确,如有错误请改正,并写出最简与或表达式:,00,01,11,10,00,01,11,10,1,1,1,1,1,1,1,00,01,11,10,00,01,11,10,1,1,1,1,1,1,1,00,01,11,10,00,01,11,10,1,1,1,1,1,1,1,1,00,01,11,10,00,01,11,10,1,1,1,1,1,1,
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