机械设计基础4第4章齿轮机构-重合度课件

单击此处编辑母版标题样式,特别申明：本电子教案中所有素材的原创作者为国防科技大学潘存云教授和王玲工程师，出版权归高等教育出版社所有。购买方有权复制多份光盘用于本单位的教学。但不得提供给第三方。未经作者同意，也不得在公开出版物中引用其中的素材，作者和高等教育出版社将保留对违反者追究相应法律责任的权利。,第二级,第三级,第四级,第五级,*,3.,重合度的物理意义,3.重合度的物理意义,1,m,=2,m,=2,m=2m=2,2,m,=2,m,=2,主动轮,基圆,啮合线,m=2m=2主动轮基圆啮合线,3,m,=2,m,=2,m=2m=2,4,m,=2,m,=2,m=2m=2,5,m,=2,m,=2,m=2m=2,6,m,=2,m,=2,m=2m=2,7,m,=2,m,=2,m=2m=2,8,m,=2,m,=2,a,=1.3,的实例,m=2m=2a=1.3的实例,9,m,=2,m,=2,局部放大,m=2m=2局部放大,10,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,现演示啮合过程,N1N2B1B2Ppb0.3pb1.3pb现演示啮合过程,11,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,N1N2B1B2Ppb0.3pb1.3pb,12,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,0.3,p,b,N1N2B1B2Ppb0.3pb1.3pb0.3pb,13,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,0.3,p,b,N1N2B1B2Ppb0.3pb1.3pb0.3pb,14,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,0.3,p,b,N1N2B1B2Ppb0.3pb1.3pb0.3pb,15,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,0.3,p,b,N1N2B1B2Ppb0.3pb1.3pb0.3pb,16,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,影线表示同时参加啮合的齿廓,N1N2B1B2Ppb0.3pb1.3pb影线表示同时参加啮,17,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,影线表示啮合点的轨迹,N1N2B1B2Ppb0.3pb1.3pb影线表示啮合点的轨,18,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,0.3,p,b,该点已达终止啮合点,B,2,同时有两对齿在啮合的啮合线长度,p,b,N1N2B1B2Ppb0.3pb1.3pb0.3pb该点已达,19,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,0.3,p,b,只有一对齿在啮合的啮合线长度,N1N2B1B2Ppb0.3pb1.3pb0.3pb只有一对,20,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,0.3,p,b,N1N2B1B2Ppb0.3pb1.3pb0.3pb,21,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,0.3,p,b,0.7,p,b,单对齿啮合的啮合线长度,*,重合度,a,表明了同时参加,啮合的齿对数的多少,重合度,a,=1.3,表示，在一个基圆齿距内,单对齿啮合的啮合线度占,70%,，,两,对齿啮合的啮合线度占,30%,N1N2B1B2Ppb0.3pb1.3pb0.3pb0.7p,22,N,1,N,2,B,1,B,2,P,p,b,0.3,p,b,1.3,p,b,0.3,p,b,0.7,p,b,重合度大，表明每对轮齿的受载小，从而提高了齿轮的承载能力。,在一般情况下，齿轮传动的重合度愈大愈好。,N1N2B1B2Ppb0.3pb1.3pb0.3pb0.7p,23,