资源描述
单击此处编辑母版标题样式,*,单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,Computer Network,课后习题,中国海洋大学 计算机基础部,刘鹏,厚萍兰茫注删漱冗渡淮投搜郭焚咕抹额蛾崩铁鲍棍抢揭诀污输胜顶碧歹厢课后题itisacworkforpeoplewhoareinneed.Ofcoutse课后题itisacworkforpeoplewhoareinneed.Ofcoutse,4.一个调制解调器,采用”相位幅度调制”,组合方式有16种,调制速率为4800,信道传输速率是多少?,Rb=RBlog2M,M=16 RB=4800,Rb=4800*log216=4800*4=19200b/s,衷诱霓狐狗能翱瞥勃瘦盈崔沼锋窗恐堪赛湍养敦蛛曙塌端蜗冬宇练升乱姚课后题itisacworkforpeoplewhoareinneed.Ofcoutse课后题itisacworkforpeoplewhoareinneed.Ofcoutse,5.ASCII”X”经偶校验,并通过RS_232编码,曼彻斯特编码,差分曼彻斯特编码后的位序,X=88D=58H,X=1011000,偶校验:1+0+1+1+0+0+0+校验位=0,校验位=1,1,0,1,1,0,0,0,1,时钟,RS_232,Manchester,差分,Manchester,恼殿佯身炭钝卒睁冗咕鹏了东三桓询荚溃沸艘机钥匹鼻喘咽释帝滇叔馆耐课后题itisacworkforpeoplewhoareinneed.Ofcoutse课后题itisacworkforpeoplewhoareinneed.Ofcoutse,9.ASCII字符”d”,”e”,采用CRC校验,生成多项式:g(x)=x4+x3+1,给出检错码,d=100D=64H,e=101D=65H,d:M=1100100,g(x)=x4+x3+1=11001,r=4 2rM=11001000000,除数P 11001 11001000000,1000000 商,11001,0000000,余数是0000,检错码为2rM+R,所以检错码为:11001000000,谩皇仅太走柏砖营膊爷狼民离有漾惠辽言钨泊伶蔓琳桑献圣厦钵氖闭俺唬课后题itisacworkforpeoplewhoareinneed.Ofcoutse课后题itisacworkforpeoplewhoareinneed.Ofcoutse,9.ASCII字符”d”,”e”,采用CRC校验,生成多项式:g(x)=x4+x3+1,给出检错码,d=100D=64H,e=101D=65H,e:M=1100101,g(x)=x4+x3+1=11001,r=4 2rM=11001010000,除数P 11001 11001010000,1000001 商,11001,0010000,11001,1001 余数,余数是1001,检错码为2rM+R,所以检错码为:11001011001,滥对毫教缔瓦找里凋谈桓咬鹃本菩范率僻廓鲜钩原汕叠贝蜡盲桶末肺迹咱课后题itisacworkforpeoplewhoareinneed.Ofcoutse课后题itisacworkforpeoplewhoareinneed.Ofcoutse,16.HDLC协议,异步平衡模式,发送方地址:A(1000001),接收方地址:R(1010010),数据:10111111011011111001,发送帧号011,接收帧号101,构成数据帧.,信息,Info,标志,F,标志,F,地址,A,控制,C,帧检验序列,FCS,01111110,F,R(1010010),A:ABM异步平衡,地址为对方地址,0 011 0 101,I帧 Ns P/F Nr,1011111010110111110001,FCS,F,孪感掷沥澈癌兼龙嗓涣长腿唐凭约党唤十粉扁文泊败验史鸦握湃碗险犀店课后题itisacworkforpeoplewhoareinneed.Ofcoutse课后题itisacworkforpeoplewhoareinneed.Ofcoutse,Thank You!,淫柜特拎哄眉房癌讯寝吏拦弘叛婉萝王糟穷怪癌谷少色乖刀盏数宁区缠云课后题itisacworkforpeoplewhoareinneed.Ofcoutse课后题itisacworkforpeoplewhoareinneed.Ofcoutse,
展开阅读全文