计算机组成原理题库.doc

第一章问题 1The computer has experienced 4 generations, which are ( ).A. Transistors, SMI, Laser device, Optical mediumB. Vacuum Tubes, Transistors, SSI/MSI circuit, Laser deviceC. Vacuum Tubes, Digital tube, SSI/MSI circuit, Laser deviceD. Vacuum Tubes, Transistors, SSI/MSI circuit, LSI/VLSI circuit问题 2The components of CPU do not include ( ).A. Arithmetic unit B. memory C. register D. controller问题 3CPU can process information of external memory directly.A.对 B.错问题 4MFLOPS is a performance index for express the speed of processing the floating point number.A.对 B.错问题 5Although computer science and technology have changed tremendously both in hardware and in software, the basic model for computers has remained essentially the same, which was presented by ( ).A. Einstein B. Von Neumann C. Edison D. Newton问题 6In 8-bits micro-computer system, multiplication and division are realized by ( ).A. dedicated chips B. firmware C. software D. hardware问题 7Software is equivalent to hardware in logic function.A.对 B.错问题 8Resources management of computer software and hardware is the duty of ( ).A. Operating System B. Language process programC. Database Management System D. Application program问题 9The reason of binary representation for information in a computer is it can easily process the information.A.对 B.错问题 10The basic feature of Von Neumann computer is ( ).A. access memory by address and execute instruction in sequenceB. access memory by contentC. Multiple Instruction Stream Single Data Stream (MISD)D. operate stack问题 11Data and instructions are stored in ( ) when the program is running.A. memory B. disk C. datapath D. operating system问题 12The operating system is appeared in ( ).A. the 4th generation computers B. the 2nd generation computersC. the 3rd generation computers D. the 1st generation computers问题 13The so called “PC” belongs to ( ).A. Medium computers B. Mainframes C. Micro-computers D. Mini-computers问题 14Computer hardware consists of calculator, memory, controller and I/O devices.A.对 B.错问题 15( ) is not belonged to system program.A. Database system B. Operating system C. Compiler program D. the above all问题 16The vast majority of computer systems used today are constructed on ( ) computer model.A. intelligent B. Von Neumann C. parallel D. real time processing问题 17The use of ( ) signified the development of micro-computer.A. software B. disk C. Microprocessor D. OS问题 18The use of microprocessor signified the development of micro-computer.A.对 B.错问题 19The reason why the binary system of representation is widely adopted in computer is ( ).A. computing speed fast B. convenience for information processingC. saving components D. the restriction of the nature of physical devices问题 20A full computer should consists of ( ).A. host and Peripheral B. calculator, memory and controllerC. host and program D. hardware and software system问题 21Host consists of CPU and I/O devices.A.对 B.错问题 22In a computer based on the von Neumann model, instructions and data are all stored in memory, and CPU distinguish them according their address. A.对 B.错问题 23System software is purchased, and applied software is edit by ourselves.A.对 B.错问题 24Which of the following languages can be implemented directly and edited by Mnemonic(助记符): Assembly language; machine language; High-level language; Operating system primitives; Regular languageA. , B. ， C. ， D. ，问题 25In computer terminology, CPU consists of calculator and controller.A.对 B.错选择题答案：1-5.DBBAB 6-10.CAABA 11-15.ACCAA 16-20.BCADD 21-25.BABBA第二章问题 1If X 2s complement = 0.1101010，then Xsign-magnitude = ( )A. 0.0010110 B. 1.0010110 C. 1.0010101 D. 0.1101010问题 2( ) is used to represent address in computer.A. 1s complement B. unsigned number C. 2s complement D. sign magnitude问题 3Numbers X1, X2 are integer, and 【X1】2s compl = 10011011，【X2】 2s compl = 00011011, then their true value of decimal form are _-101_ and _27_。问题 4The sign-magnitude representation of 0 is unique.A.对 B.错问题 5Plus two 2s complement numbers that adopt 1 sign bit, overflow must occur when ( ).A. carry signal is generated from the sign bitB. XOR operation for carry signal generated from the sign bit and carry signal generated from the highest numerical bit is 0C. XOR operation for carry signal generated from the sign bit and carry signal generated from the highest numerical bit is 1D. XOR operation for carry signal generated from the sign bit and carry signal generated from the highest numerical bit is 1问题 6The range of representation for a 1s complement number system of 64 bits (including the sign bit) is ( ).A. 0|N|263 1 B. 0|N|262 1 C. 0|N|264 1 D. 0|N|263问题 7Fixed point number can be classified into pure decimal(纯小数) and pure integer(纯整数).A.对 B.错问题 8In fixed point calculator, whether adopted double sign bit or single sign bit, it must has ( ), which is often implemented by ( ).A. Decoding circuit, NAND gate B. encoding circuit, NOR gateC. overflow detection circuit, XOR gate D. shift circuit, AND-OR gate问题 9Arithmetic shift 2s complement of a positive, sign bit remains unchanged, and the blank bit fills in 0. Arithmetic left shift 2s complement of a negative, sign bit remains unchanged, and the low bit fills _0_. Arithmetic right shift 2s complement of a negative, sign bit remains unchanged, and the high bit fills_1_, and truncat low bit.问题 10Let the word length is 8, the fixed point integer with 2s complement representation of -1 is _11111111_.问题 11In fixed point operation, it will be overflow when the result exceeds the represent range of the computer.A.对 B.错问题 12For a 8-bit 2s complement representation integer number, its minimal value is_-128_, its maximal value is_127_.问题 13A fixed point number is composed of sign bit and numerical part.A.对 B.错问题 14The range of representation for a 2s complement number system of 16 bits (including the sign bit) is ( ).A. -215 + (215 -1) B. - (215 1) + (215 1) C. -215 + 215 D. - (215 +1) + 215 问题 158-4-2-1 BCD code of a number is 0111 1000 1001， then its true value is_789_.问题 16The addition/subtraction algorithm for sign magnitude representation is rather simple.A.对 B.错问题 17Which of the following numbers is odd parity?A. 010110011 B. 001000111 C. 110100111 D. 110100111问题 18The number represented in the computer sometimes will be overflow, the fundamental reason is the limited computer word length.A.对 B.错问题 19For fixed point binary calculator, subtraction is implemented through ( ).A. 2s complement binary subtractor B. 2s complement binary adderC. sign magnitude decimal adder D. sign magnitude binary subtractor问题 20In 2s complement addition/subtraction, using 2 sign bits for overflow detection, when the 2 sign bits S1S2 equals 10, it means that ( ).A. result is positive, with no overflow B. result is negative, with no overflowC. result is overflow D. result is underflow问题 21The 2s complement representation of -127 is 10000000.A.对 B.错问题 22The minimal number of the following numbers is ( ).A. （100101）2 B. （100010）BCD C. （50）8 D. （625）16问题 232s complement representation of 0 equals to 1s complement representation of -1.A.对 B.错问题 24If X2s complement = 1.1101010，then Xsign-magnitude = （）A. 1.0010101 B. 1.0010110 C. 0.0010110 D. 0.1101010问题 25For sign magnitude representation, 1s complement representation, 2s complement representation,_ sign magnitude representation _ and_1s complement representation _has 2 representations of 0.问题 26The use of 2s complement operation is adopted to simplify the design of computer.A.对 B.错问题 27Fixed point calculator is used for ( ).A. fixed point operation B. floating point operationC. fixed point operation and floating point operation D. decimal addition问题 28When -1xEy, shift_My_; if ExEy, shift_Mx_; if Ex=Ey, no shift.问题 3The mantissa of floating point number uses 2s complement representation, the binary code of the mantissa before normalization is 1.10101. It needs_left_ normalization, and it should shift_1_bit.问题 4( ) representation is used in mantissa of floating point number.A. biased code or excess-2q code B. sign magnitudeC. 2s complement D. 1s complement问题 5In the representation of floating point numbers, （ ）is implicit(隐含)A.exponent B. the radix of the number system to represent the mantissaC. mantissa D. sign bit问题 6For a IEEE 754 standard Floating-Point number, its mantissa uses ( ) representation.A. biased code or excess-2q code B. 1s complementC. sign magnitude D. 2s complement问题 7Which of the followings is correct:A. Exponent unit can realize addition, subtraction, multiplication and division operations.B. Mantissa unit only realize multiplication and subtraction operations.C. Exponent unit only realize addition and subtraction for exponent.D. Floating point calculator can be implemented by exponent and mantissa units.问题 8The maximal positive number in IEEE754 standard for 32-bits format is （）A. +（2 2-23）2+255 B. +（2 2-23）2+127C. +（1 2-23）2+127 D. 2+127 + 227问题 9Exponent unit in floating point calculator can realize operations of addition, subtraction and compare.A.对 B.错问题 10Which is normalized Floating-Point number, if its mantissa is represented by 2s complement format?A. 0.01110 B. 1.00010 C. 0.01010 D. 1.11000问题 11In IEEE 754 standard, a floating point number is composed of sign bit s, exponent e, and mantissa m.A.对 B.错问题 12 The sign bit 1 of a biased code number represents the number for_非负数_, while 0 represents the number for_负数_.问题 13In IEEE754 standard floating point, mantissa is coded as_原码_, exponent is coded as_移码.问题 14In IEEE 754 standard, the value of exponent is represented in excess-128 code.A.对 B.错问题 15In a algorithm for normalized float-point number, a number is 251.10101, with 2s complement representation for mantissa. Then it ( ).A. needs left shift 2 bits of mantissa for normalized B. needs left shift 1 bit of mantissa for normalized.C. needs no normalized D.needs right normalized问题 16The exponent, E, of a floating point number usually uses biased code representation, which is more convenient for comparing size or exponent equalization.A.对 B.错问题 17The mantissa of a Floating-Point number is represented by 2s complement, then whether the Floating-Point number is normalized is decided by ( ).A. mantissas sign bit and the first bit of mantissas numerical part are identicalB. the sign bit of exponent and mantissa are identicalC. mantissas sign bit and the first bit of mantissas numerical part are differentD. the sign bit of exponent and mantissa are different问题 18In the representation of floating point numbers,_基数_ is implicit and invisible to the computer hardware.问题 19The purpose of using normalized floating point number is ( ).A. to expand the range of data representation B.to avoid for overflowC. convenient for floating point operation D. to ensure maximum accuracy of representation问题 20( ) representation is used in exponent of Floating-Point number.A. biased code or excess-2q code B. 1s complementC. sign magnitude D. 2s complement1.B 2. My Mx 3. left 1 4-10.BBCDBA11.A 12. 非负数 负数 13.原码 移码 14-15.BB16-17.AC 18.基数 19-20.DA第七章问题 1Indirect addressing mode is designed to facilitate the access of data arrays.A.对 B.错问题 2Instruction set is a key factor to represent the performance of a computer.A.对 B.错问题 3Register-Register (RR) addressing mode is slower than Register-Storage (RS) addressing mode.A.对 B.错问题 4The function of program control instructions is （ ）.A.to perform arithmetic and logic operations B.to move data between I/O and CPU C.to move data between memory and CPU D.to change the program executing order 问题 5According to storage position of operand, the instruction set usually supports SS addressing mode.A.对 B.错问题 6An instruction word consists of Opcode and addresses part.A.对 B.错问题 7Format and function of instruction set only affect the hard structure of a computer.A.对 B.错问题 8In register indirect addressing mode, the operand is in ( ).A.PC B.stack C.memory D.general register 问题 9The operand is in a register, this addressing mode is called （ ）.A.register direct addressing mode B.direct addressing mode C.indirect addressing mode D.register indirect addressing mode 问题 10The address part in a program control instruction represents the address of next instruction that needs transfer.A.对 B.错问题 11In the instruction addressing modes the fastest way to get the operand is ( ).A.register addressing mode B.direct addressing mode C.indirect addressing mode D.immediate addressing mode 问题 12In order to implement arithmetic operation between two operands for one-address instruction, one operand is indicated by addresses part of instruction, another operand is specified by ( ).A.immediate addressing mode B.implied addressing mode C.stack addressing mode D.indirect addressing mode 问题 13By using different addressing mode, the instruction set can ( ).A.reduce the instruction length, expand addressing space, improve programming flexibility B.realize program store and program control C.access external storage directly D.extend OPcode and decrease the trouble of instruction decoding. 问题 14For the number of instructions, addressing mode and instruction kinds, RISC is less than CISC.A.对 B.错问题 15There are two instruction addressing modes, one is sequential, and the other is jump. Jump addressing mode can perform ( ).A.conditional branch of program B.conditional or unconditional branch of program C.unconditional branch of program D.stack addressing 问题 16The purpose of using extending Opcode in instruction format is （ ）.A.to keep the length of instructions, while increase the addressing space B.to increase the length of instructions C.to keep the length of instructions, while increase the kinds of instruction operate D.to reduce the length of instructions 问题 17Which instruction has the maximal execution time（ ）?A.Program control instructions B.RS instructions C.SS instructions D.RR instructions 问题 18Let the valid address of operand is given in the address part of instruction, then the instruction adopts ( ).A.immediate addressing mode B.indirect addressing C.register direct addressing mode D.direct addressing mode 问题 19OPcode in an instruction gives