数学教学课件ACOUSTIC ENCLOSURES AND BARRIERSPPT

CHAPTER FIVEACOUSTIC ENCLOSURES AND BARRIERS 5.1 SOUND TRANSMISSION LOSSAirborne STL is defined as follows: 101STL10logWhere is:1. Airborne STL Transmitted soundRefracted and absorbed soundIncident soundReflected soundAbsorption coefficient:iriIIITransmission coefficient: tiIIIncident: Incident: I Ii i Reflected: Reflected: I Ir rAbsorbed: Absorbed: I Ia aTransmitted: Transmitted: I It tSound Insertion loss (IL) The difference in sound pressure measured in a single location with and without a noise-control device located between the source and receiver. The difference in the sound pressure measured in the occupied space with the wall versus without the wall is the IL of the wallSound transmission loss (TL) It equals to the ratio of the airborne sound power incident on the partition to the sound power transmitted by the partition and radiated on the other side.IL and TL101TL10logSourceBarrierIn a roomWe have known:i= absorption coefficient of i th surfaceiiiASFor i th surface:niiiAS For a whole room: the room-averaged sound absorption coefficient , : niiiSSASS is the total surface area of the room.Also, in a roomTransmitted soundRefracted and absorbed soundIncident soundReflected soundeqiiSS iieqSStiII10Also, in a roomeqiiSS iieqSSThe corresponding sound transmission loss is given by :101STL10logeq101R10logeqWe assume :Another form :exampleWall: 20m2, walldoorwindows5110Door: 2m2, Windows: 3m2, 32102310Calculate the STL.exampleWall: 20m2, walldoorwindows5110Door: 2m2, Windows: 3m2, 32102310STL=10log105=50 dBSTL=10log103=30 dBSTL=10log102=20 dBAverage transmission loss required for various levels of speech privacyAverage Transmission loss of wall, dBHearing conditionsRating30 or lessNormal speech can be understood quite easily and distinctly through the wall.Poor30-35Loud speech can be understood fairly well. Normal speech can be heard but not easily understood.Fair35-40Loud speech can be heard, but is easily intelligible. Normal speech can be heard only faintly, if at all.Good not40-45Loud speech can be faintly heard but not understood. Normal speech is inaudible.Very goodrecommended for dividing walls between apartments.45 or greaterVery loud sounds, such as loud singing, brass musical instruments, or a radio at full volume can be heard only faintly or not at all.Excellentrecommended for band rooms, music practice rooms, radio and sound studios,2. STL in a separated roomSound transmission loss is calculated by:SpeakerMicrophone(Receiver)Room2Partition(Source)12Room11210STL10logSLLAL1L2The is obtained as follows: The sound power impinging on the test specimen from the source side is 24sspWScS= surface area of test specimen, m2 ssWI S(4.8)4scI22spc1210STL10logSLLAIn the source roomIn the receiver room The rate of energy transmission into the room equals the rate of energy absorption, at steady-state conditions. Thus (4.12)rWIA24rrp AWcOr(4.8)4cI22rpcL1SpeakerMicrophone(Receiver)Room2Partition(Source)12Room1Sound transmission loss is calculated:24sspWScL224rrp AWcrsWWtiII22srp SpA From the definition of transmission coefficient: 22srp Sp A210210logsrp SSTLp A22101022/10log10log/srefrrefppSppA221010102210log10log10logsrrefrefppSppA121010logSLLA3. Sound transmission class STC STC is a single-number rating used primarily to rate the speech privacy of a barrier or other structure. It is determined from a plot of STL data measured in 1/3-octave bands (or octave bands) from 125 to 4000 Hz. (NRC)STC following conditions:1. The STL value at any frequency cannot be more than 8 dB below the STC contour.2. The sum of all deficiencies (STL less than contour value) at all frequencies cannot exceed 32 dB. 3. The STC value is obtained from the STL value of the highest-valued contour at 500 Hz. The sound transmission class number is used to rate the acoustic performance of walls, floors, ceilings, doors, folding partitions, panels and other architectural structures. Test data curveSTC 46STC contourTransimission loss, dBBand center frequency, Hz125 200 320 500 800 1250 2000 3200 5000100 160 250 400 630 1000 1600 2500 4000 63006050403020100频率频率参考量参考量100-19125-16160-13200-10250-7315-4400-1500063018002100031250416004200042500431504 Can we always find the STC for sound transmission loss of a panel?STC ratings for various levels of speech privacy25303540454850NormalLoudLoudLoudMustSomeLoudSpeech can be understood quite easilySpeech can be understood fairly wellSpeech audible but not intelligibleSpeech audible as a murmurstrain to hear loud speechLoud speech barely audibleSpeech not audibleSTC ratings for common building materialsMaterial STC rating1/4-in steel plate361/4-in plate glass263/4-in plywood284-in brick wall416-in concrete-block wall421/2-in gypsum board on both sides of 2 x 4studs3312-in reinforced-concrete wall5614-in cavity wall (8-in brick2-in air space 4-in brick)65 国家标准民用建筑隔声设计规范（GBJ118-88）中，对住宅分户墙的隔声性能规定是：一级住宅50dB，二级住宅45dB，三级住宅40dB . 参考发达国家相关标准，将我国住宅分户隔墙的空气声计权隔声量的实验室测量值均定为不应小于50dB，现场测量值不应小于45dB；套内分室隔墙的空气声计权隔声量，实验室测量值均定为不应小于35dB，现场测量值不应小于30dB。 表表 各国住宅分户隔墙隔声最低要求对比表各国住宅分户隔墙隔声最低要求对比表 单位： dB注：Rw和DnT，w分别为墙体隔声量的实验室测量值和现场测量值。国家隔声澳大利亚一户居室与另一户厨房、卫生间相邻时其间分户墙Rw50，其余Rw45英国Rw50德国Rw54丹麦Rw54新西兰Rw55美国STC（Rw）50或DnT，w45dB中国现场测量隔声量404. Insulation value of combined structural elements It is often necessary to calculate the net insulation value of two structural elements acting in combination. The net insulation of a wall with a window, a partition with a door or a roof with a rooflight, can be obtained by calculation if the insulation values of each element are known. exampleWall: 20m2, walldoorwindows5110door: 2m2, windows: 3m2, 32102310iieqSS101TL10logeq532315 102 103 101.6 1020eq 101TL10log27eqdBExample: Let us assume that a class rooms have 6mm fixed glazing of average insulation 26 dB set in a wall with an insulation value of 50 dB and that the ratio of window to wall is 2:1. calculate the Insulation value of combined windows and wall?wallWindowsglazing0 5 10 15 20 25 30 35 40 45 50 55 60 dB1 3 5 10 15 20 25 30 35 40 45 50 55 60 dB Difference1:2501:1251:641:321:161:81:41:21:12:14:18:1Loss of insulation (deduct from higher insulation)Ration of two areas (lower to higher insulation)Ratio of areas: 2:1Difference in insulation: 50 26 = 24 dBFrom graph, loss of insulation = 23 dBTherefore net insulation of wall and window = 50 23 =27 dBWall 50dBWindowsGlazing 26 dB0 5 10 15 20 25 30 35 40 45 50 55 60 dB1 3 5 10 15 20 25 30 35 40 45 50 55 60 dB Difference1:2501:1251:641:321:161:81:41:21:12:14:18:1Loss of insulation (deduct from higher insulation)Ration of two areas (lower to higher insulation)exercise A class rooms have fixed glazing of average insulation 20 dB set in a wall with an insulation value of 45 dB and that the ratio of window to wall is 1:4. calculate the Insulation value of combined windows and wall?The hole effects of STL on the wall 1 12212SSSSFor the wall and hole, we set:102111S2S21 12212SSSS121201SSSS 212SSSUsually, 12SS21SS102121SSS2/S1STL dB1/1000301/100201/10101/23Equal STLwallwindow21SSIn our design, We assume:1122SSWhich means if we want to improve the STL, we should improve the windows STL .Ratio of areas: 2:1Difference in insulation: 50 26 = 24 dBFrom graph, loss of insulation = 23 dBTherefore net insulation of wall and window = 50 23 =27 dB Wall 50dBWindowsGlazing 26 dBAttenuation versus Dissipation of Acoustic Energy Note !Transmitted soundRefracted and absorbed soundIncident soundReflected soundAbsorption coefficient:iriIIITransmission coefficient: tiIIIncident: Incident: I Ii i Reflected: Reflected: I Ir rAbsorbed: Absorbed: I Ia aTransmitted: Transmitted: I It t The guideline that a good absorber is a poor barrier is illustrated by the following example. Consider a sound wave impinging on the surface of an absorbing structure. If 80 percent of the incident intensity is absorbed, 10 percent is reflected, and 10 percent is transmitted, then 1.0STL10log10dB0.1=10log=10dB=33dBabsorbedabsorbedreflectedreflectedtransm ittedtransm ittedE1E1E1E1E1E1E1E1=10log1011081010.11.0TL10096.5TL0.00051.01000.0510031010Absorption and transmission-loss characteristics of absorbers and barriers end