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经济数学基础(经济数学基础(3)第)第26讲(讲(1) 第四章习题解答第四章习题解答2、已知在曲线上任一点切线的斜率为、已知在曲线上任一点切线的斜率为x2并且曲线过点并且曲线过点)2, 1 ( ,求此曲线方程,求此曲线方程,解:解:3,3,122,122222xyccyxcxxdxxdxyxy曲线方程为所以解得代入上式得时当4、求下列不定积分、求下列不定积分dxxxx)3(3(1)解:解:cxxxdxxdxxxdxdxxxx34232312134932213)3(dxxxx)2((2)解:解:cxxxdxdxxdxxxdxxxx2252323215422)2()(dxxx3(3)解:解:cxdxxdxxx3734373dxxx221(4)解:解:cxxdxxdxdxxxdxxxarctan11111122222dxxx1(5)解:解:cxxdxxdxdxxxdxxx|1 |ln111111dxeexx112(6)解:解:cexdxedxdxedxeeedxeedxeexxxxxxxxxx)()()()(1111111122dxxx)2(1(7)解:解:cxxxxdxxdxxdxxxdxxx|2|ln21|2|ln|ln212112121121)2(1)()()(dxx2tan(8)解:解:cxxdxxdxdxxdxxtansec1sectan222)(dxx2cos2(9)解:解:cxxxdxxxdxxxdxxdxdxxdxxsin2121cos21212cos12sin2sin12cos222)(dxxxx32532(10)解:解:cxcxdxdxdxxxxxxx)()()(323ln2ln5232ln32523252325325、求下列不定积分、求下列不定积分dxx100) 1((1)解:解:cxxdxdxxxdxx101100100100) 1(10111) 1(1) 1() 1()()(dxx2941(3)解:解:cxxdxdxxxdxxdxx23arctan6123231161232313241231419412222)()()()()(5)解:解:dxxx21cxcxxdxdxxxdxxx23223222222)1 (31)1 (3221112111211)()(7)解:解:dxxx ln1cxcxxdxdxxxdxxxln2)(ln2lnln1lnln1ln121)(dxxx)sin(ln(8)解:解:cxxdxdxxxdxxx)cos(lnln)sin(ln)(ln)sin(ln)sin(lndxeexxsin(9)解:解:cedeedxeedxeexxxxxxxcossinsinsin)(dxxex2(11)解:解:cedxedxxedxxexxxx222221212122)(12)解:解:dxxx2costancxxxddxxxdxxx22tan21tantantantancostan)(13)解:解:dxxx2sincoscxxdxdxxxdxxx1222)(sinsinsin1sinsin1sincos)(15)解:解:dxxxx2212cxxxxdxxxdxxxdxxdxdxxxdxxxdxxxdxxxdxxxx)()()(222222222222221lnarctan111arctan111111211112112(16)解:解:dxxex23cexdedxxedxxexxxx222232323361)361361()(dxx2941(17)解:解:cxxxdxxdxdxxxdxxxdxxdxxdxxxdxxxdxx)32ln()32ln(121)32(32131323213141)32(321313232131413213214132132141323219412)()()()()(6、求下列不定积分、求下列不定积分xdxxln(1)2211lnxvdxxduxdvxu解:解:cxxxxdxxxxdxx22241ln2121ln21lndxxex2(2)解:解:cexexdexedxexedxxexxxxxxx22222224121241212121)(xxevdxdudxedvxu2221dxxxln(4)解:解:cxxcxxxcxxxdxxxxxdxxx)(2ln24ln222ln22ln2ln21dxxvdxxdudxxdvxu211lndxexx ) 1((5)解:解:cexeceexdxeexdxexxxxxxxx211) 1()()(xxevdxdudxedvxu1dxxx2cos(6)解:解:cxxxxdxxxdxxx|cos|lntantantancos2xvdxdudxxdvxutancos12xdxx ln2(7)解:解:cxxxdxxxxxdxx3323291ln3131ln31ln32311lnxvdxxdudxxdvxudxxex2sin(8)解:解:cxexedxxexexedxxexdxexexexdxexexexdxexedxxexxxxxxxxxxxxxxx2cos522sin512sin2cos22sin2sin52sin42cos22sin2sin22cos 22sin2cos22sin2sinxxevxdxdudxedvxu2cos22sinxxevxdudxedvxu2sin22cosxdxexsin2(10)解:解:cxexexdxexexexdxexdxexexexdxexexexdxexexdxexxxxxxxxxxxxxxxcos51sin52sincos41sin21sin45sin41cos41sin21sin21cos2121sin21cos21sin21sin222222222222222xxevxdudxedvxu2221cossinxxevxdudxedvxu2221sincosdxex12(12)解:解:cxectecetedtetetdtedxexttttttx)()(11211212tdtdxtxtx)(令121122ttevdtdudtedvtu
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