模拟电子电路习题课

,单击此处编辑母版标题样式,单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,*,多路电流源,I,B,由于各管的,、,V,BE,相同，所以有：,I,E0,R,0,I,R,R,0,=,I,E1,R,1,=,I,E2,R,2,=,I,E3,R,3,当,较大时，,I,C0, I,E0,I,R,8.,场效应管组成的,差分放大电路,电路,R,d1,10k,R,d2,10k,R,g2,1M,R,g1,1M,R,3,2.7k,R,1,20k,R,2,3.3k,V,DD,12V,-V,SS,-12V,v,id,v,o2,T,1,T,2,T,3,T,4,比例电流源,差分放大电路例题,1,v,i1,v,i2,v,o,例,1:,=50,，,求,(1),静态工作点,(2),A,d,R,o,和差模输入电阻,R,i,d,例题,1,静态分析,例题,1,动态分析,差分放大电路例题,2,v,+V,CC,T,1,T,2,+,R,R,R,_,-V,+,_,R,C,v,i,L,e6,o,EE,e3,T,3,T,4,T,5,T,6,C4,R,680,5.1,K,350,150,10,K,10,V,-10,V,第一级,第二级,例,1,：,=100,，,r,bb,=100,，,静态时,v,o,=0V,(1),计算静态电流,(2),计算差模放大倍数,例题,2,静态分析,例题,2,动态分析,例,3,：电路如图，静态时，,Vo=0,。求,R=,？,T,5,T,6,T,3,T,4,R,8,3.6,K,R,9,5.1,K,R,3,10,K,R,4,10,K,R,5,1.8,K,R,2,1M,R,6,6K,R,7,6K,R,v,i,+15,V,-12,V,T,1,T,2,R,1,1M,v,o,解：,(1),静态分析：,I,C3,=I,C4,=2mA,V,R5,=2 I,C4,R,5,=7.2V,V,R3,=V,R4,= V,R5,+V,BE3,=7.9V,例,3,静态分析,I,D1,=I,D2,=0.79mA,V,R8,= V,R9,= 2 I,D2,R,8,=5.7V,V,R,=12-0.7- V,R8,=5.6V,I,R9,= V,R8,/ R,9,=1.1mA,R= V,R,/ I,R9,=5.1K,T,5,T,6,T,3,T,4,R,8,3.6,K,R,9,5.1,K,R,3,10,K,R,4,10,K,R,5,1.8,K,R,2,1M,R,6,6K,R,7,6K,R,v,i,+15,V,-12,V,T,1,T,2,R,1,1M,v,o,例,3,动态分析,设,=150,，,g,m,=3mA/V,，,r,be3,=r,be4,=2.16k,输入输出同相,T,5,T,6,T,3,T,4,R,8,3.6,K,R,9,5.1,K,R,3,10,K,R,4,10,K,R,5,1.8,K,R,2,1M,R,6,6K,R,7,6K,R,v,i,+15,V,-12,V,T,1,T,2,R,1,1M,v,o,例,4,：分析电路,解：,T,1,、,T,2,：,单端输入,双端输出,T,3,、,T,4,：,双端输入,双端输出,例,4,静态分析：,例,4,动态分析：,例5,例6,例7 (1),例7 (2),10K,5V,静态时,V,O,=5-10I,C1,=2.4V,V,O,=0.8V,则：,V,O,= -1.6V,V,I,=1V时,V,O,=5V时,Vo =Vi,Avd,=47V,例8,A,vd,= -,g,m,R,L,R,L,=20K/5K,例9,静态时,V,O,=0,I,C3,= I,E3,= 1mA,I,E1,+I,E2,=0.24mA,I,C1,= I,C2,= 0.12mA,V,RC,=0.25I,E3,+0.7=0.95V,R,C,= V,RC,/I,E3,= 7.9K,R,i2,= r,be3,+(1+,)R,E3,第一级,第二级,例10,静态时,V,O,=0,I,C5,= I,E5,= 2.55mA,2I,D,+0.7=(15+1) I,C2,I,Re,=2I,C2,R,e,= (12-0.7)/I,Re,V,GS,= - 2I,D,R,i2,= r,be3,+(1+,)R,E3,R,i3,= r,be5,+(1+,)R,E5,1,2,3,例11,（,1,）静态分析,（,2,）计算放大倍数、,输入输出电阻。,=50,r,be,=1.2k,T1,：,共射极,T2,：,共基极,例,12,v,i,=0,时,v,o,=0,1.,计算,T,1,、,T,2,、,T,3,的工作电流,2.,计算电路的电压放大倍数,v,o,/v,i,(,只需要列出表达式）,T,1,T,2,T,4,T5,T,3,R,1,4.7,k,R,2,4.7,k,R,3,10,k,R,4,10,k,R,5,5.6,k,R,6,12,k,R,7,10,k,R,8,R,9,10,k,+15,-15,v,i,v,o,习题,1,习题,2,开立方运算,习题,3,例,1:,设计一加减运算电路,设计一加减运算电路，使,V,o,=2V,i1,+5V,i2,-10V,i3,解：用双运放实现,如果选,R,f1,= R,f2,=100K,，且,R,4,= 100K,则：,R,1,= 50K R,2,= 20K R,5,= 10K,平衡,电阻,R,3,= R,1,/ R,2,/ R,f1,= 12.5K,R,6,= R,4,/ R,5,/ R,f2,= 8.3K,V,i2,-,+,A,1,R,f1,R,3,V,o1,R,2,V,i1,R,1,-,+,A,2,R,f2,R,6,V,o,R,4,V,i3,R,5,V,i,-,+,A,1,R,3,V,o,I,2,R,1,I,i,-,+,A,2,2R,2,R,3,R,2,I,1,V,o2,例,2,：,如图电路，求,A,vf,，,R,i,解：,R,i,例,3,：求电路的电压放大倍数,A,vf,A,1,R,1,R,8,R,2,v,o,R,3,R,4,v,i,R,7,R,6,R,5,A,2,A,3,v,+3,v,o3,v,+1,例,4:,求,v,o,与,(,v,s1,-,v,s2,),的关系,v,s1,-,+,2,R,-,+,-,+,3,R,3,R,4,R,4,R,2,R,1,R,v,s2,v,o1,v,o2,v,o,A,1,A,2,A,3,v,3,v,4,由于第一级差放电路上下对称，,R,1,的中点可视为接地点，所以：,例,4,应用实例,应用实例,例,5,：精密整流电路,V,i,V,o,V,i,0,时，,D2,截止，,D1,导通，,V,o1,=- V,i,，,V,o,=- V,i,-2 V,o1,=,V,i,V,i,0,时，,D1,截止，,D2,导通，,V,o1,=0,，,V,o,=- V,i,V,o,=V,i,V,o1,V,i,-,+,A,R,2,R,4,V,o,I,f,R,1,I,i,I,d,I,4,R,3,I,3,R,2.,T,型反馈网络,虚短、虚断,如果要求放大倍数,100,，,R,1,=R,2,=R,4,=100K,，,R,3,=1.01K,