c语言上机大题

、程序设计 共113题（共计1130分） 第1题（10.0分）题号:390 【程序设计】功能:编写函数求1100中奇数的平方和。结果为 !66650. 000000/#include void wjt ();float sum(int n)(/*Program*/* End */答案:float s=0;int i;for(i=l;i=n;i=i+2)s=s+i*i;return (s);第2题（10.0分）题号:320 【程序设计】功能:在键盘上输入个3行3列矩阵的各个元素的值（值 为整数）,然后输出主对角线元素的积,并在fun（） 函数中输出。*/include void wwjt ();main ()(int i, j, s, a3 3;for(i=0;i3;i+)(for(j=0;j3;j+)scanf (*%d*, &ai j);)s=fun(a);printf(*Sum=%dn*,s);wwjt ();int fun (int a33)(/*Program*/* End */ void wwjt()(FILE *IN,*0UT;int m;int n;int i33;int o;IN二fopen (in. dat, r); if(IN=NULL)(printf(Read FILE Error);OUT=fopen(out. dat, w); if(OUT=NULL)printf(Write FILE Error)：)for(m=0;m3;m+)for (n=0; n3; n+)fscanf (IN, %d, &i m n)：=fun ；fprintf (OUT, %dn, o);getchO ：)fclose(IN);fclose(OUT);答案:int sum;int i, j;sum=1;for(i=0;i3;i+)sum=sum*ai i;return sum;第3题(10.0分)题号:324/*【程序设计】功能:能计算从1开始到n的自然数中偶数的平方的和,n由 键盘输入,并在main。函数中输出。(n是偶数)*/include void wjt ();int fun(int n)/* End */main ()(int m;printf(*Enter m:);scanf(%cT, &m);printf(*nThe result is %dn*, fun(m); wwjt ();void wwjt() FILE *IN, *0UT;int t;int o;int c;IN二fopen (in. dat, r);if(lN=NULL)printf(Read FILE Error*);OUT=fopen (ut. dat, w);if(OUT=NULL)(printf(Write FILE Error);)for(c=l;c=5;c+)fscanf (IN, %d, &t);o=fun(t);fprintf (OUT, %dn, o);)fclose(IN);fclose(OUT);答案:一int sum, i;sum =0;for(i=2;i=n;i=i+2)sum=sum+i*i; return(sum);第4题(10.0分)题号:345 【程序设计】功能:将两个两位数的正整数a、b合并形成一个整数放在c 中。合并的方式是：将a数的十位和个位数依次放在 c数的千位和十位上,b数的十位和个位数依次放在 c数的个位和百位上。例如：当a=45, b=12.调用该函数后,c=4251.*/#include void wwjt ();void fun(int a, int b, long *c)(/*Program*/* End */main()(int at b;long c;printf(*input a, b:);scanf (%d%d”, &a, &b);fun (a, b, &c);printf(The result is: %ldn*, c);wwjt ();void wwjt ()(FILE *rf, *wf ;int i, a, b ;long c ;rf = fopen(in. dat, r );wf = fopen (out. dat, w);for(i = 0 ; i 10 ; i+)(fscanf (rf, %d, %d, &a, &b);fun (a, b, &c);fprintf (wf, a=%d, b=%d, c=%ldn, a, b, c);)fclose(rf);fclose (wf);)答案:*c=a/l0*1000+a%10*10+b/10+b%10*100;第5题(10.0分)题号:366/*【程序设计】功能:求一组数中大于平均值的数的个数。例如:给定的组数为1,3,6,9,4,23,35,67, 12, 88时,函 数值为3。* /#include void wwjt ();int fun(int a, int n)/* End */main ()(int a10 = l, 3, 6, 9, 4, 23, 35, 67,12, 88;int y;y=fun (a, 10);printf(y=%dn”,y);wwjt ();void wwjt ()(FILE *IN, *OUT;int iIN10, iOUT, i, j;IN=fopen (in. dat, r);if(IN=NULL)printf(Please Verify The Currernt Dir. it May Be Changed);)OUT=fopen(out. dat, w);if(OUT=NULL)(printf(Please Verify The Current Dir. it May Be Changed);for(j=0;j10;j+)(for(i-0;i10;i+)fscanf(IN, %d,&iINi);iOUT=fun(iIN, 10);)fprintf(0UT, %dn, iOUT);fclose(IN);fclose(OUT)：)答案:int i,k=0;float s=0,ave;for(i=0;in;i+)s+=ai;ave=s/n;printf (*%f *, ave);for(i=0;iave)k+;return k;第6题（10.0分）题号:355/*【程序设计】功能:对长度为8个字符的字符串,将8个字符按降序排列。 例如:原来的字符串为CEAedcab,排序后输出为edcbaECAo* /#include#include#includevoid wwjt ();void fun (char *s, int num)(/ *Prograiii*/* End */main ()(char s 10;printf (输入8个字符的字符串:)； gets(s);fun(s, 8);printfi n%s , s);wwjt ();void wwjt ()int i;char a100;FILE *rf, *wf ;rf = fopen(in. dat, r );wf = fopen(outdat, w);for(i=0;i3;i+)(fscanf (rf, %s, &a);fun (a, 8);fprintf (wf, %s”, a);fprintf (wf, ”n)；)fclose (rf);fclose (wf);)答案:int i, j;char t;for (i=0;inum;i+)for(j=i+l;jnum;j+) if(sisj) t=si;si=sj;sj=t;第7题(10.0分)题号:44/*【程序设计】功能:求出维数组周边元素之和,作为函数值返回。二 维数组的值在主函数中赋予。define M 4#define N 5#include void wwjt ();int fun(int aM N)/*Program*/* End */ main()(int aM N = 1,3, 5, 7, 9, 2, 4, 6,8, 10, 2, 3,4, 5,6, 4, 5, 6, 7, 8: int y;y=fun(a);printf(s二%dn, y);wwjt ();void wwjt ()(FILE *IN, *OUT;int iINMN, iOUT;int i, j, k;IN二fopen(14. IN, r);if(INNULL)printf(*Please Verify The Currernt Dir. it May Be Changed);)0UT=fopen(14. out, w);if(OUT=NULL)printf(*Please Verify The Current Dir. it May Be Changed*);)for(k=0;k10;k+) for(i=0;iM;i+)for(j=0;jN;j+) fscanf (IN, %d,&iINi j);iOUT二fun(iIN);fprintf (OUT, %dn, iOUT);fclose(IN);fclose(OUT)：答案:-int s=0;int i, j;for(i=0;iM;i+)s=s+ai 0+ai N-1;for(j=l;jN-l：j+)s=s+a0 j+aM-l j; return s;第8题(10.0分)题号:339/*【程序设计】功能:判断整数x是否是同构数。若是同构数,函数返回1； 否则返回。x的值由主函数从键盘读入,要求不大 于 100。说明:所谓“同构数”是指这样的数,这个数出现在它的 平方数的右边。例如：输入整数5, 5的平方数是25, 5是25中右侧的数，所 以5是同构数。*/#include void wwjt();int fun(int x)(/*Program*/* End */ main()int x, y;printf(*nPlease enter a integer numbers:*);scanf (%d, &x);if(x100)(printf(data error!n);exit(0);)y=fun (x);if (y)printf(%d YESn,x);elseprintf(%d N0n, x);wwjt ();void wwjt ()FILE *IN, *OUT;int n, t;int o;IN=fopen(in. dat, r);if(IN=NULL)printf(Read FILE Error);)OUT=fopen (out. dat, w);if(OUT=NULL)(printf(Write FILE Error);)for(t = 0 ; t 5 ; t+)(fscanf(IN, %d, &n);o=fun(n);fprintf (OUT, %dn, o );fclose(IN);fclose(OUT);答案:int k;k=x功能:用函数实现字符串的复制,不允许用strcpyO函数。 include void wwjt ();void copy(char strl, char str2)(/*Prograni*/* End */)main()(void copy ();char cl40,c240;gets(cl);copy (cl, c2);puts (c2);wwjtO ;void wwjt ()功能:计算并输出给定整数n的所有因子之和（不包括1与 自身）。注意:n的值不大于100。例如:n的值为855时,应输出704。*/#include void wwjt （）;int fun(int n)x;if(k%10=x)I I(k%100=x) return 1;elsereturn 0;第9题（10.0分）题号:383/*【程序设计】FILE *IN, *OUT;char i100;char o100;IN=fopen(in. dat, r); if(IN=NULL) (printf(Read FILE Error);)OUT=fopen(out. dat, w); if(OUTNULL) (printf(Write FILE Error);)fscanf (IN, %s, i);copy (i, o);fprintf(OUT, %sn, o);fclose(IN);fclose(OUT);n int i;for(i=0;strli!=、;i+) str2i=strli;str2i= 0;第10题（10.0分） 题号:310 【程序设计】/*Program*/* End */ main ()(printf(*s=%dn*,fun(855);wwjt ();void wwjt() FILE *IN, *0UT;int ilN, iOUT, i;IN=fopen (in. dat, r);if(IN=NULL)printf(Please Verify The Currernt Dir. it May Be Changed);)0UT=fopen (out. dat, w);if(OUT=NULL)(printf(Please Verify The Current Dir. it May Be Changed);)for(i=0;i5;i+)(fscanf(IN, %d,&iIN);iOUT=fun(iIN);fprintf (OUT, %dn, iOUT);fclose(IN);fclose(OUT)：)答案:int s=0, i;for(i=2;in;i+) if(n%i=O)s=s+i：return s;第11题（10.0分）题号:354 【程序设计】功能:求小于lim的所有素数并放在aa数组中,该函数返回 所求出素数的个数。;*/#include#includeconio. h#define MAX 100void wjt ();int fun(int 1im, int aaMAX)(/*Program*/* End */main()(int limit, i, sum;int aaMAX;printf(*Please input ainteger:*);scanf (%d”, &1 imit);sum=fun(limit, aa);for(i=0;isum;i+) if(i%10=0&i!=0) printf (*n*);printf (%5d”, aai);)wwjt ();void wwjt ()(int i, j, array 100, sum, lim;FILE *rf, *wf ;rf = fopen(in. dat, r);wf = fopen(out. dat, w);for (j=。;j = 5; j+)(fscanf(rf, %d, &lim);sum=fun (1 im, array);for (i=0;isum;i+)fprintf (wf, %7d, arrayi);fprintf (wf, n);)fclose(rf);fclose(wf);答案:int n=0;int i, j;for (i=2;i=lim;i+)for(j=2;ji;j+)if(i%j=0) break;if(j=i) aan+=i;)return n;第12题（10.0分）题号:341/*【程序设计】功能:删除所有值为y的元素。数组元素中的值和y的值由 主函数通过键盘输入。*/#include #include#includestdio. hdefine M 20void wjt ();void fun(int bb, int *n,int y) (/*Prograrn*/* End */main()int aaM, n, y, k;printf(*nPlease enter n:);scanf(飞d”, &n);printf(nEnter %d positive number:n*, n);for(k=0;kn;k+) scanf(%d”, &aak);printf The original data is:n);for(k=0;kn;k+) printf(%5d”, aak);printf(*nEnter a number to deletede:);scanf(%d, &y);fun (aa, &n, y);printf(The data after deleted %d:n”, y);for(k=0;kn;k+) printf(%4d, aak);printf(n);wwjt ();void wwjt ()(FILE *IN, *OUT;int n;int i10;int o;IN=fopen(in. dat, r);if(IN=NULL)(printf(Read FILE Error);)OUT=fopen (out. dat, w);if (OUTNULL)printf(Write FILE Error);for(n=0：n10：n+)fscanf(IN, %d”,&in);)fun(i,&n, 3);for(o=0;on;o+)(fprintf (OUT, *%dn*, i 0);)fclose(IN);fclose(OUT);答案:-int i, j;for(i=0;i*n;)if(bbi=y)for(j=i;j*n;j+) bbj=bbj+l;*n=*n-l;elsei+;第13题（10.0分） 题号:317 【程序设计】功能:求出NXM整型数组的最大元素及其所在的行坐标及 列坐标（如果最大元素不唯一,选择位置在最前面 的个）。例如:输入的数组为:123415 612 18 910 11 2求出的最大数为18,行坐标为2,列坐标为1。ttdefine N 4define M 3include void wwjt ();int Row, Col;int fun(int arrayNM)/*Program*/* End */ mainO(int aN M, i, j, max;printf(input a array:);for(i=0;iN;i+)for(j=0;jM;j+)scanf(%d”, &aij);for(i二;iN;i+)(for(j=0;jM;j+)printf(%d*,aij);printf(n);)max=fun(a);printf (max=%d, row=%d, col=%d”, max, Row, Col); wwjt ();void wwjt ()FILE *IN, *OUT;int iINN M, iOUT, i, j;IN=fopen (in. dat, r);if(IN=NULL)printf(Please Verify The Currernt Dir. it May Be Changed); OUT=fopen (out. dat, w);if(OUT=NULL)(printf(Please Verify The Current Dir. it May Be Changed); )for(i=0;iN;i+)for (j=0; jM; j+)fscanf(IN, %d,&iINi j);iOUT=fun(iIN);fprintf (OUT, %d %d %dn, iOUT, Row, Col);fclose(IN)：fclose(OUT);答案:int max, i, j;max二array 00;Row;Col=0;for(i=0;iN;i+)for(j=0;jM;j+)if(maxarray i j)max=array i j;Row=i;Col=j;return(max);第14题（10.0分）题号:392/*【程序设计】功能:求一批数中最大値和最小值的积。define N 30include *stdlib. h*include void wwjt ();int max_min(int a,int n)(/*Program*/* End */ main ()(int aN, i, k;for(i=0;iN;i+)ai=random(51)+10;for(i=0;iN;i+)(printf(*%5d*, ai);if(i+l)%5=0) printf(n);k=max_min(a, N);printf(*the result is:%dn , k);wwjt ();)void wwjt ()(FILE *IN,*0UT;int n;int i10;int o;IN=fopen (in. dat, r);if(IN=NULL)printf(Read FILE Error);OUT二fopen (out. dat, w);if (OUTNULL)(printfCWrite FILE Error);for(n=0;n10;n+)(fscanf(IN, %d,&i n);)o=max_min(i, 10);fprintf (OUT, %dn, o);fclose(IN);fclose(OUT);)答案:int i, max, min;max=min=a0;for(i=l;imax) max=ai;else if(aimin) min=ai;return(max*min);第15题(10.。分)题号:501include 【程序设计】题目:从键盘输入一个大写字母,要求改用小写字母输出。t/#include void wjt ();char fun(char c)(/*Program*/* End */void main()char cl, c2;printf(*Please input a char:*);cl=getchar();printf (*%c,%dn*, cl, cl);c2=fun(cl);printf (*%c, %dn”, c2, c2);wwjt ();void wwjt ()(FILE *IN, *OUT;int i;char ilN, iOUT;IN二fopen (in. dat, r);if(IN=NULL)(printf(Please Verify The Currernt Dir. it May Be Changed);)0UT=fopen(out. dat, w);if(OUTNULL)(printf(Please Verify The Current Dir. it May Be Changed);)for(i=0;i5;i+)(fscanf(IN, %c,&iIN);iOUT=fun(iIN);fprintf(OUT, %cn, iOUT);)fclose(IN);fclose(OUT);)答案:c=c+32;return c;第16题(10.0分) 题号:502#include /*【程序设计】题目:用while语句求1100的累计和。*/ void wwjt ();int fun(int n)(/*Program*/* End */void main ()(int sum = 0;sum=fun(100);printf (sum = %dn, sum);wwjt ();)void wwjt()(FILE *IN, *0UT;int i;int ilN, iOUT;IN=fopen(in. dat, r);if(IN=NULL)printf(Please Verify The Currernt Dir.it May Be Changed);OUT=fopen (*out. dat, w);if(OUT=NULL)(printf(Please Verify The Current Dir. it May Be Changed);)for(i=0;i5;i+)fscanf(IN, %d,&iIN);iOUT=fun(iIN);fprintf (OUT, %dn, iOUT);)fclose(IN);fclose(OUT);答案: int i=l, sum=0;while(i=n)sum=sum+i;i+；return sum;第17题(10.0分) 题号:409/*-【程序设计】题目:输入华氏温度求摄氏温度。转换公式为c=5/9 (f-32), 输出结果取两位小数。*/include void wwjt ();double fun(double m)/*Program*/* End */void main ()double c, f;printf (请输入个华氏温度:);scanf (%f, &f);c=fun(f);printf (摄氏温度为:5. 2fn, c);wwjt();void wwjt ()(FILE *IN, *OUT;int i;double ilN,iOUT;IN=fopen(in. dat, r);if(IN=NULL)(printf(Please Verify The Currernt Dir. it May Be Changed);)0UT=fopen(out. dat, w);if(OUTNULL)(printf(Please Verify The Current Dir. it May Be Changed);)for(i=0;i5;i+)(fscanf (IN, %f,&iIN);iOUT=fun(iIN);fprintf(OUT, %fn, iOUT);)fclose(IN);fclose(OUT);)答案:float n;n=(5. 0/9. 0)*(m-32);return n;第18题（10.0分）题号:29 【程序设计】功能:对任意输入的x,用下式计算并输出y的值。5x10；*/#includevoid wwjt ();int fun(int n)(/*Prograni*/* End */void main ()(int x, y;printf(enter x:);scanf C%d &x);y=fun (x);printf (*x=%d, y=%dn*, x, y);wwjt ();)void wwjt ()FILE *IN,*0UT;int i;int ilN;long int iOUT;IN=fopen(in. dat, r);if(IN=NULL)(printf(Please Verify The Currernt Dir. it May Be Changed); )OUT=fopen(out. dat, w);if(OUTNULL)(printf(Please Verify The Current Dir. it May Be Changed*); )for(i=0;i5;i+)(fscanf(IN, %d,&iIN);iOUT=fun(iIN);fprintf(OUT, %ldn, iOUT);)fclose(IN);fclose(OUT);答案:int m;if(n=10)if(n10)m 5;else m二。;else m=5;return m;第19题(10.0分)题号:382 【程序设计】功能:给定n个数据,求最小值出现的位置(如果最小值 出现多次,求出第一次出现的位置即可)。*/#include void wwjt ();int station(int s,int n)/*Prograni*/* End */main()int a100, n, i, t;scanf (%d, &n);for (i=0; i n;i+)scanf (%d”, &ai);t=station(a, n);printf(*the min_value position is:%dn,t);wwjt ();void wwjt ()FILE *IN,*OUT;int n;int i10：int o;IN二fopen (in. dat, r);if(IN=NULL)printf(*Read FILE Error*);OUT二fopen(ut dat, w);if(OUT=NULL)(printfCWrite FILE Error*);)for(n=0;n10;n+)(fscanf(IN, *%1*, &i n);o=station(i,10);fprintf(OUT, %dn*, o);fclose(IN);fclose(OUT);答案:-int i, k;k=0;for(i=l;in;i+)if(sisk) k=i;return(k);第20题(10.分)题号:367 【程序设计】功能:找出批正整数中的最大的偶数。#/#include void wjt ();int fun(int a, int n)/*program*/* End */ main ()(int a = l,2, 9, 24,35, 18 ,k;k=fun(a, 6);printf (max=%dn”, k);wwjt();void wwjt ()(FILE *IN, *OUT;int iIN10, iOUT, i, j;IN=fopen (in. dat, r);if(IN=NULL)printf(Please Verify The Currernt Dir. it May Be Changed);)OUT=fopen(out. dat, w);if(OUT=NULL)(printf(Please Verify The Current Dir. it May Be Changed);for(j=0;j10;j+)(for(i-0;i10;i+)fscanf(IN, %d,&iINi);iOUT=fun(iIN, 10);)fprintf (OUT, %dn, iOUT);fclose(IN);fclose(OUT)：)答案:int i, amax=-l;for(i=0;iamax) amax=ai;return amax;第21题（10.。分）题号:384/功能:产生20个30, 120上的随机整数放入二维数组a5 4 中,求每行元素的和。 include *stdlib.h*#include void wjt ();void row_sum(int a54, int b5)(/*Program*/* End */main ()(void row sum();int a5 4, b5, i, j;for(i=0;i5;i+)for(j=0：j4;j+)aij=random(120-30+1)+30;for(i=0;i5;i+)(for(j=0;j4;j+)printf (%5d, ai j);printf(n);【程序设计】)row_sum(a, b);for(i=0;i5;i+)printf(*%6d*,bi);printf(n);wwjt();void wwjt ()FILE *IN,*OUT;int m, n;int i54;int o5;IN二fopen (in. dat, r);if(IN=NULL)(printf(Read FILE Error);)OUT=fopen(out. dat, w);if(OUTNULL)(printf(Write FILE Error);)for(m二;m5;m+)for(n二;n4;n+)fscanf (IN, %d, &i m n);row sum(i, o);for(n=0;n5;n+)fprintf (OUT, %dn, on);fclose(IN);fclose(OUT);答案:int i, j;for(i=0;i5;i+) bi=0;for(j=0;j4;j+) bi=bi+aij;第22题(10.0分)题号:334 【程序设计】功能:求给定正整数n以内的素数之积。(n28)#include #include*conio. h void wwjt ();long fun(int n)(/*Prograni*/* End */ main ()(int m;printf Enter m:;scanf (%d, &m);printf(*nThe result is %ldn*, fun(m);wwjt ();void wwjt ()(FILE *IN, *OUT;int c ;int t;long o;IN=fopen (in. dat, r);if(IN=NULL)printf(*Read FILE Error*);)OUT=fopen (*out. dat, w);if (OUTNULL)(printf(Write FILE Error);)for(c=l;c=5;c+)(fscanf (IN, %d, &t);o=fun(t);fprintf(OUT, %ldn,o);fclose(IN);fclose(OUT);答案:long i, k;long s=l;for(i=2;i=n;i+)for(k=2;ki;k+) if(i%k=0)break; if(k=i)s=s*i；return s;第23题(10.0分)题号:363/*【程序设计】功能:求一个给定字符串中的字母的个数。*/#include void wwjt ();int fun(char s)/*Program*/* End */ main ()(char str=*Best wishes for you!int k;k=fun (str);printf(k二dn, k);wwjt ();void wwjt()(FILE *IN, *OUT;char sin80;int iOUT, i;IN二fopen (in. dat, r);if(IN=NULL)(printf(Please Verify The Currernt Dir. it May Be Changed);)0UT=fopen(out. dat, w);if(OUT=NULL)(printf(Please Verify The Current Dir. It May Be Changed);)for(i=0;iI0;i+)(fscanf (IN, %s, sin);iOUT=fun(sin);)fprintf(OUT, %dn, iOUT);fclose(IN);fclose(OUT);答案:int i, k=0;for(i=0;si !=、0; i+)if (si=a&si z | |si=A&si=Z) k+;return k;第24题（10.0分）题号:361 【程序设计】功能:编写程序,求矩阵(3行3歹)与2的乘积 例如:输入下面的矩阵:100 200 300400 500 600700 800 900程序输出:200 400 600800 1000 12001400 1600 1800*/#include void wwjt ();void fun(int array33) (/*Prograni*/* End */ mainOint i, j;int array 3 3 = 100, 200, 300, 400, 500, 600,700, 800, 900;for (i二; i 3; i+)for (j=0; j 3; j+)printf(*%7d*, arrayij);printf(n);)fun (array);printf(Converted array:n);for (i=0; i 3; i+)(for (j=0; j 3; j+)printf(%7d, arrayij);printf(n)：)wwjt ();void wwjt ()(int i, j, array33;FILE *rf, *wf ;rf = fopen (in. dat, r);wf = fopen (out. dat, w);for (i=0; i 3; i+)for (j=0; j 3; j+)fscanf(rf, %d, &arrayij);fun (array);for (i=0; i 3; i+)for (j=0; j 3; j+)fprintf (wf, %7d, arrayi j);fprintf (wf, n);)fclose(rf);fclose(wf);答案:int i, j;for(i=0; i 3; i+)for(j=0; j 3; j+)arrayij=arrayij*2;第25题（10.0分）题号:400 【程序设计】功能:编写main程序调用函数fact求解从m个元素选n个元 素的组合数的个数。计算公式是: 组合数=01!/(山.(111