资源描述
单击此处编辑母版标题样式,单击此处编辑母版文本样式,第二级,第三级,第四级,第五级,*,1,某校为了了解七年级,350,名学生的数学学习情况,从该年级任意抽取了,50,名学生进行测试,结果如下,(,单位:分,),93,,,92,,,75,,,77,,,72,,,73,,,84,,,67,,,95,,,84,,,86,,,71,,,96,,,84,,,85,,,89,,,92,,,74,,,73,,,83,,,40,,,68,,,81,,,98,,,94,,,89,,,92,,,99,,,70,,,82,,,72,,,93,,,68,,,85,,,86,,,75,,,83,,,78,,,92,,,60,,,89,,,52,,,96,,,83,,,92,,,86,,,67,,,77,,,57,,,77,分组,频数统计,频数,39.549.5,49.559.5,59.569.5,69.579.5,79.589.5,89.599.5,合计,(1),请你完成下面的频数分布表:,1,2,5,13,16,13,50,(2),画出频数直方图;,频数,分组,0,2,4,6,8,10,12,14,16,18,20,39.5,49.5,59.5,69.5,79.5,89.5,99.5,(3),试估计该校七年级有多少名学生数学成绩在,80,分,(,含,80,分,),以上,经计算,这,50,名学生测试结果达到,80,分以上的占,58%,,用这,50,名学生测试达到,80,分以上的比率估计七年级,350,名学生成绩达到,80,以上的人数,即,35058%,203(,人,).,2,某林业局对林区内树木的生长情况进行抽样调查,测得一些树干的树围长度,(,单位:,m),,并列出如下的频数分布表:,分组,0.40.5,0.50.6,0.60.7,0.70.8,0.80.9,0.91.0,1.01.1,1.11.2,频数,3,9,18,30,20,10,7,3,(1),画出频数直方图;,频数,分组,0,3,6,9,12,15,18,21,24,27,30,0.4,0.5,0.6,0.7,0.8,0.9,1.0,1.1,1.2,(2),求树围长度为,0.6,1.0m,之间的树木数占总树木数的百分率,抽出的树木中树围长度为,0.6,1.0m,之间的树木数为,78,棵抽出的数目总数为,100,棵,因此估计树木中树围长度为,0.6,1.0m,之间的树木占总树木数的百分率为,78%,
展开阅读全文