南航机械原理缝纫机课程设计230

目录1 目22 原始数据33 44 杆件 度的 算65 主要 算 果76 用解析法 滑 行B 运 分析97 用 解法 两个极限位置和一个一般位置 行运 分析128E 点的运 迹179 MATLAB程序代 1910 B 点的位移、速度、加速度数据 2011 E 点的坐 数据 21 12参考 目 221 设计题目缝纫机导线及紧线机构设计及其运动分析结构示意图 :该机构由 O1 轴上齿轮驱动齿轮2， O2 轴上还固接有曲柄 O 2A 和 O2C ，曲柄滑块机构 O 2 AB 的滑块为缝纫针杆，曲柄摇杆机构 O2O3DC 的连杆上点 E 为紧线头，针杆与紧线头协调动作，完成缝纫和紧线过程。原始数据方案号一齿轮转数n1rpm齿轮转数n 2rpm模数mmm中 心 距O1O 2mm距离Lmm针杆冲程Hmm杆长O2O3mm杆长O3Dmm角度1deg2deg3degdegdeg杆长DE / DC2002301.2554403634294212014410801.3O2A / AB0.33 齿轮设计由传动比公式知可取 z146 ， z140 。1，标准中心距m( z1 z2 )1.25 (4640)d253.75mm22，齿轮啮合时的压力角由得d cosd cosarccosd cosarccos73.75cos2020.7165d543，分度圆直径d1mz11.254657.5mmd2mz21.254050mm4，基圆直径db1 d1 cos57.5cos2054.03232mmdb2d2 cos50cos2046.98463mm5，变位系数由inv2( x1x2 ) taninvz1z2即inv 20.71652( x1x2 ) tan 20 inv 204640得x1 x20.20108取x10.05108, x20.156，中心距变动系数yz1z2 ( cos1)46 40 (cos201) 0.202cos2cos20.71657，齿高变动系数y( x1x2 )y0.001088，齿轮机构的传动类型正传动9，齿顶高ha1(ha*x1y)m(1 0.05108 0.00108) 1.25 1.3125mmha 2(ha*x2y)m(1 0.150.00108) 1.251.43615mm10，齿根高hf 1(h *c*x )m (10.25 0.05108) 1.251.49865mma1h f 2( h* ac*x2 )m(1 0.25 0.15) 1.251.37511，齿顶圆直径da1d12ha57.52 1.312560.125mmda 2d22ha5021.4361552.8723mm12，齿根圆直径d f 1d12hf 157.52 1.4986554.5027mmd f 2d22h f 25021.37547.25mm13，齿顶圆压力角rb127.0161626.0167a1arccosarccosra130.0625a 2arccos rb 2arccos23.4923227.2967ra 226.4361514，分度圆上的齿厚s1m1.252x1m tan2 0.05108 1.25 tan 20 2.00997mm22s2m2x2m tan1.2520.15 1.25tan202.09998mm2215，齿顶厚r a130.0625sa 1s1 r12 ra 1 ( inva 1inv)2.0099728.75230.0625( inv 26.0167inv 20)0.95719 mmsa 2s2ra 22 ra 2 ( inva 2inv)2.0999826.43615r225226.43615(inv 27.2967inv 20)0.91351 mm经检验sa10.4 m0.41.250.5 mmsa 20.4m0.41.250.5mm16，重合度a1 z1(tan a1tan) z2(tan a2tan)1 46(tan26.0167 tan20.7165)2240(tan27.2967 tan20.7165)1.6835经检验 a(1.1 1.2)4 杆件长度计算由针杆冲程 H 可得lO2AH3618mm22由lO2 A0.3得l ABAB60mm设 D 的两个极限位置为D1, D2所以，在D1O3 D2 中l D1 D22lO3 D sin22 29 sin 80 1033.26743mm23901449054由余弦定理得l CDlO Cl O2DlO2O2lO D lO Ocos()233233229234222934cos(5480)58.02470mml CDlO2C222lO3D lO3O2cos()lO3 Dl O3 O229234222934cos(5410)33.65311mm所以，有以上两方程得lCD45.83891mmlO2C12.18580mmlDE由于1.3lCD所以lDE1.345.8389159.59058 mm5 主要计算结果计算项目z1z2ad1d2db1db 2x1x2x1x2yha1ha 2hf 1hf 2da1da 2d f 1结果464053.75mm20 4357.5mm 50mm54.03232mm46.98463mm0.201080.051080.150.001081.3125mm1.43615mm1.49865mm1.375mm60.125mm52.8723mm54.5027mmd f 2a1a 2s1s2sa1sa 2lO2 Al ABlO2 ClCDl DE47.25mm26 127 182.00997mm2.09998mm0.95719mm0.91351mm1.683518mm60mm12.18580mm45.83891mm59.59058mm6 用解析法对滑块进行B 运动分析lO2 A cos3)0l AB sin(2所以lO2 A coslAB cos0ylO2 AsinlABcos(3) lO2 AsinlABsinB2由以上两式可得yBlO2 A sinlAB 1lO Acos )2( 2lABy18sin60 1(0.3cos)2B对应的位移曲线如下对上式求导得vB18cos2.7sin 21(0.3cos)2433.53972cos65.03096sin 21(0.3cos)2对应的速度曲线如下再对上式求导得aB18 2 sin2 5.4cos 2 (1 0.09cos2) 0.1215sin 2 21(0.3cos)2 3210442.03827sin580.113245.4cos 2(10.09cos2) 0.1215sin 2 21 (0.3cos)2 32对应的加速度曲线图如下7 用图解法对两个极限位置和一个一般位置对应的速度加速度计算，并将结果与解析法的结果比较O2 A2 n224.08554 rad60s1 极限点一：901.1 速度分析(mm)速度比例尺：v100scmv Bv Av BA大小：?O2 AO2 A?方向：BAO2 ABA由图可得（图见坐标纸）v B0vpa1004.35435mmBAsABvBA4357.25radlAB60s1.2 加速度分析(mm 2 )加速度比例尺：a2000scmaaaanBABABA大小：？2lO A？AB 2l AB2方向：BAAO2BAB A由图可得（图见坐标纸）aBaa 2000 3.6 7200 mms2方向水平向右AB0由解析法得到的结果如下v B0vBA433.53972mmsAB7.22566rad saB7309.4285mm s2方向水平向右AB02 极限点二：2702.1 速度分析100(mm)速度比例尺：vscmv Bv Av BA大小：？O2 A O2 A？方向：B AO2 ABA由图可得（图见坐标纸）v B0vBApa1004.35 435mmsABvBA4357.25radl AB60s2.2 加速度分析加速度比例尺：a2000(mms2 ) cma Ba AaanBABA大小：？2lO2 A？AB2l AB方向： BAA O2BABA由图可得（图见坐标纸）aBab 2000 6.8 13600 mm2方向水平向左sAB0由解析法得到的结果如下v B0vBA433.53972mmsAB7.22566radsaB13574.64975mms2方向水平向左AB03 一般位置243.1 速度分析(mm)速度比例尺：v100scmvBv Av BA大小：？lO2 A？方向：BOO2 AAB2由图可得（图见坐标纸）vBAv ab1001.8180 mmsBAvBA1803 radl AB60svBvpb 100 3.45 345 ms3.2 加速度分析(mms2 )加速度比例尺：a 1000cma BaAaBAna BA大小？2lO2 AAB 2lAB？方向B O2AO2BAAB由图可得（图见坐标纸）aBab1000 6.356350 mms2方向水平向右由解析法得到的结果如下vBA183.35694 mmsBAvBA183.356943.055595radsl BA60v345.80677mBsaB6382.97554 mm2方向水平向右s8，E 点的运动轨迹O3 点坐标为xO3lO2O3cos34cos19.98470 mmyO3lO2O3 sin34sin27.50658mmD 点坐标xDlO2O3coslO3D cos19.98470 29cosyDlO2O3 sinlO3D sin27.50658 29sin三角形 O2O3D 中，由余弦定理可得lODlO2O3lO2 D2lO O lO D cos()223233342292234 29cos(54)由正弦定理有lO2 O3lO2 Dsin 1sin()所以lO2O3sin()34sin(54)1arcsinlO2 D arcsinlO2D由余弦定理得l2l22O2 DCDlO2Ccos 22lO2D l CD所以lO222lO2l22DlCDlO CDCDlO C2 arc cos 22lO2 D lCD2arc cos 22lO2D lCD2所以2(12 )所以xExDl DE cosyEyDl DE sin并且54l O O34mmlO D29mm，23，3，lO C12.18580 mm，lCD45.83891mm，2lDE59.59058mm ，2 120联立以上各方程可以画出E 点轨迹如下9， MATLAB 程序代码位移曲线x=0:0.0001:2*pi;y1=18*sin(x);y2=60*sqrt(1-0.09*(cos(x).2);y=y1-y2;plot(x,y);速度曲线a=0:1:360x=a*pi./180;y1=18*cos(x);y2=2.7*sin(2*x);y3=sqrt(1-0.09*(cos(x).2);y=(y1-y2./y3)*24.08554plot(x,y);加速度曲线a=0:0.0001:360;x=a.*pi./180;y1=18.*sin(x);y2=5.4.*(cos(2*x);y3=(1-0.09.*(cos(x).2);y4=0.1215.*(sin(2*x).2;y5=(1-0.09*(cos(x).2).1.5;y=(0-y1-(y2.*y3-y4)./y5).*24.085542;plot(x,y);E 点的运动轨迹曲线a=10.*pi./180:0.0001:80.*pi./180;b=54.*pi./180;o3x=-34.*cos(b);o3y=34.*sin(b);dx=o3x+29.*cos(a);dy=o3y+29.*sin(a);o2d=sqrt(34.*34+29.*29-2.*34.*29.*cos(a+b);r1=asin(34.*sin(a+b)./o2d);r2=acos(o2d).2+45.83891.2-12.18580.2)./(2.*(o2d).*45.83891);ex=dx+59.59058.*cos(120.*pi./180+a+r1+r2-pi);ey=dy+59.59058.*sin(120.*pi./180+a+r1+r2-pi);plot(ex,ey);11. B 点的位移、速度、加速度数据角度（ ）位移（ mm)速度（ mm/s)加速度（ *10000mm/s2)0-57.2364433.5397-0.32845-55.3960419.5697-0.356210-54.1960403.6721-0.488515-54.2640382.6548-0.532620-51.4101363.8259-0.604025-4902235334.6655-0.645230-48.9396317.1352-0.678435-47.8654285.2145-0.693240-46.8239266.3064-0.719745-45.9654235.3256-0.723550-45.0851213.4059-0.737255-44.2852183.2654-0.738660-43.7327159.8069-0.740465-43.1235135.2356-0.739670-42.7689106.2564-0.737075-42.532686.2354-0.736880-42.192053.0112-0.732785-42.086525.1254-0.731590-42.00000-0.730995-42.0980-25.1256-0.7315100-42.1920-53.0112-0.7327105-42.4562-86.2354-0.7331110-42.7689-106.2564-0.7370115-42.7523-135.2356-0.7395120-43.7327-159.8069-0.7404125-44.0567-183.2654-0.7386130-45.0851-213.4059-0.7372135-45.1254-235.3256-0.7245140-46.8239-266.3064-0.7197145-47.3265-285.2145-0.6923150-48.9396-317.1352-0.6784155-49.2464-334.6655-0.6523160-51.4101-363.8259-0.6040165-52.1656-382.6548-0.5324170-54.1960-403.6721-0.4885175-56.2354-419.5697-0.4256180-57.2364-433.5397-0.3284185-59.0123-445.3566-0.2456190-60.4473-450.2344-0.1259195-61.2395-450.56840.0025200-63.7229-450.96220.1103205-64.2354-443.25460.2354210-66.9396-433.77760.3658215-68.2546-413.65920.4562220-69.9643-397.91500.6227225-71.2356-375.36540.7562230-72.6627-343.94200.8626235-73.5656-300.24680.9654240-74.9096-273.73281.0682245-75.2114-293.26541.1235250-76.5978-190.30221.2254255-77.0123-100.26651.2986260-77.6451-97.55551.3239265-77.9654-46.55661.3452270-78.000001.3575275-77.965446.55661.3698280-77.645197.55551.3239285-77.0123100.26651.3211290-76.5978190.30221.2254295-75.2114293.26541.1235300-74.9096273.73281.0682305-73.5656300.24680.9654310-72.6627343.94200.8626315-71.2356375.36540.7562320-69.9643397.91500.6227325-68.2546413.64920.5241330-66.9396433.77760.3658335-64.2354443.25960.2415340-63.7229450.96220.1103345-61.2395450.56840.0025350-60.4473450.2344-0.1259355-59.0123443.2546-0.2456360-57.2364433.5397-0.328412.E 点的坐标数据（与对应）a( ）Ex(mm)Ey(mm)1066.066148.21981561.077162.15532057.819668.97522554.820174.35533051.922178.90573549.061182.86784046.205986.36194543.343389.45335040.472292.17725537.603194.54946034.75996.56996531.982598.21987029.356399.44457527.0864100.07878027.230298.160713，参考书目朱如鹏主编，机械原理 . 修订 2 版. 北京：航空工业出版社，1998.8韩立竹，王华编著，北京：国防科技出版社，MATLAB电子仿真与应用，2001.1C+书目王洪欣主编，机械原理课程上机与设计，南京：东南大学出版社，2005.8