分式方程专项练习50题

分式方程专项练习50题 分式方程专项练习50题 13 = xx+2 2x=1 x-12x+1=4 1-x5x-3+=0 xx 21= x-1221-=0 x+1x-113 =xx-2x1-=1 x+1x-12x-53 =x-22-x2x1 -1=x+1x+1x+43x+2=2x+1 x+x3x1-= 2x-4x-222x2-=1 2x-52x+5x11 x32x624x3 -1=x-22-x2x+=1 xx+33x2-12=2x x+232 =1+x+3x-1x2-2=1 x-2x-4x+424=2 x-1x-12x5=1 +2x+55x-2105=2 +2x-11-2x23x+3-=2 x-1x+1x-1x2x+1 +1=x+1xxx-1+=2 x+1x32 =xx-12x2+1 =2x x+2x1+=1 x-1x23-=0 x-2xx+23=0 x-1x(x-1)12 =x-1x+1x-24+2=1 x+2x-4316 +=2x+1x-1x-123 =x-1x+1124 +=2x+1x-1x-1x2x=+1 x+13x+33-x1 +=1x-44-x x5 =1-2x-55-2xx+14-2=1 x-1x-1mn-=0(mn,mn0) xx+111 =x2+5x-6x2+x+62-x1+-1=0 x-33-x3x1-= 2x-4x-22x2x = +1 x+13x+32y3y-1 +1=y-1y x43 xx1 |x|-5=0 2x+5xx-2 =x-22-xx+ 114 +=2x-3x+3x-9111x-y=3 11=2xy9答案： 13 = x=1 xx+2 x+2x+4x+6x+8-=- x+1x+3x+5x+72x=1 x=-1 x-12x+11=4 x= 21-x5x-3+=0 x=2 xx 21= x=5 x-1221-=0 x=3 x+1x-113 x=-1 =xx-2x1-=1 x=0 x+1x-12x-53 x=1 =x-22-x2x1 x=2 -1=x+1x+1x+43x+2=2x+1 x=4 x+x53x1-= x= 32x-4x-222x235-=1 x= 2x-52x+56x11 x2 x32x624x35 x=- -1=x-22-x32x +=1 x=6 xx+33x2-12=2x x=6 x+272x5=1 x= +2x+55x-231057=2 x= +42x-11-2x23x+3-=2 x=1是增根所以原方程无解 x-1x+1x-11x2x+1 x=- +1=2x+1x1xx-1+=2 x=- 2x+1x32 x=3 =xx-112x2+1 =2x x= 4x+2x11+=1 x= 2x-1x23-=0 x =6 x-2xx+23=0 x-1x(x-1) 检验x=1 是原方程的增根 所以，原方程无解 12 x=3 =x-1x+1x-24+2=1 x=3 x+2x-4316 x=2 +=2x+1x-1x-123 x=5 =x-1x+1124 x=1是增根所以原方程无解 +=2x+1x-1x-1x2x3=+1 x=- x+13x+323-x1 +=1x-44-x x5 x=0 =1-2x-55-2xx+14-2=1 x=1为增根，此题无解； x-1x-1mnm -=0(mn,mn0) x=n-mxx+111 x=3 =22x+5x-6x+x+62-x1+-1=0 x=2 x-33-x3x15-= x= 32x-4x-22x2x3 = +1 x x+13x+322y3y-11+1=y= y-1y 3x43 x2 xx1 |x|-5=0 x=5 x2+5xx+ x-2 x=-1 =x-22-x114 x=2 +=2x-3x+3x-9111x-y=3 112=xy93x2=-3x1=2，3 y=-22y1=3x+2x+4x+6x+8 -=-x+1x+3x+5x+71111-1-=1+-1- x+1x+3x+5x+71111 - =-x+1x+3x+5x+7 原方程化为1+ 方程两边通分，得22 =(x+1)(x+3)(x+5)(x+7) (x+5)(x+7)=(x+13)(x+) 化简得8 x=-32 解得x =-4 经检验：x是原方程的根。 =-4